+91-8076753736 support@wiredfaculty.com
logo
logo

A PHP Error was encountered

Severity: Notice

Message: Undefined variable: temp_qds

Filename: Questions_Page/Ncert_Question.php

Line Number: 320

Backtrace:

File: /home/wiredfa1/public_html/application/views/final/Questions_Page/Ncert_Question.php
Line: 320
Function: _error_handler

File: /home/wiredfa1/public_html/application/controllers/Home.php
Line: 235
Function: view

File: /home/wiredfa1/public_html/index.php
Line: 315
Function: require_once

Sponsor Area

Continuity And Differentiability

Question
CBSEENMA12034698
Wired Faculty App

Differentiate space square root of 3 straight x plus 2 end root plus fraction numerator 1 over denominator square root of 2 straight x squared plus 4 end root end fraction straight w. straight r. straight t space space straight x.

Solution
Let space straight y equals square root of 3 straight x plus 2 end root plus fraction numerator 1 over denominator square root of 2 straight x squared plus 4 end root end fraction equals left parenthesis 3 straight x plus 2 right parenthesis to the power of 1 half end exponent plus left parenthesis 2 straight x squared plus 4 right parenthesis to the power of negative 1 half end exponent therefore space dy over dx equals 1 half left parenthesis 3 straight x plus 2 right parenthesis to the power of negative 1 half end exponent. straight d over dx left parenthesis 3 straight x plus 2 right parenthesis plus open parentheses negative begin inline style 1 half end style close parentheses left parenthesis 2 straight x squared plus 4 right parenthesis to the power of negative 3 over 2 end exponent. straight d over dx left parenthesis 2 straight x squared plus 4 right parenthesis space space space space space space space space space space space space space equals fraction numerator 1 over denominator 2 square root of 3 straight x plus 2 end root end fraction. left parenthesis 3 right parenthesis minus fraction numerator 1 over denominator 2 left parenthesis 2 straight x squared plus 4 right parenthesis bevelled 3 over 2 end fraction. left parenthesis 4 straight x right parenthesis therefore space dy over dx equals fraction numerator 3 over denominator 2 square root of 3 straight x plus 2 end root end fraction minus fraction numerator 2 straight x over denominator left parenthesis 2 straight x squared plus 4 right parenthesis bevelled 3 over 2 end fraction

Some More Questions From Continuity and Differentiability Chapter

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation