+91-8076753736 support@wiredfaculty.com

Sponsor Area

Continuity And Differentiability

Question

Wired Faculty App

Differentiate the following w.r.t.x: $straight e to the power of straight x cubed end exponent$

Solution

Let space space space space space space space space straight y equals straight e to the power of straight x cubed end exponent therefore space space space dy over dx equals straight e to the power of straight x cubed end exponent. straight d over dx left parenthesis straight x cubed right parenthesis equals straight e to the power of straight x cubed end exponent. left parenthesis 3 straight x squared right parenthesis equals 3 straight x squared straight e to the power of straight x cubed end exponent

Some More Questions From Continuity and Differentiability Chapter

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation