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Continuity And Differentiability

Question
CBSEENMA12034685

Differentiate the following w.r.t.x: straight e to the power of straight x squared end exponent

Solution
Let space space space space space space space space space space space space straight y equals straight e to the power of straight x squared end exponent
therefore space space space space space space space dy over dx equals straight e to the power of straight x squared end exponent. straight d over dx left parenthesis straight x squared right parenthesis equals straight e to the power of straight x squared end exponent.2 straight x equals 2 straight x space straight e to the power of straight x squared end exponent

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