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Continuity And Differentiability

Question
CBSEENMA12034518

Find A so that f(x) is continuous at x = 0.
straight f left parenthesis straight x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell fraction numerator 1 minus cos space 8 straight x over denominator 4 straight x squared end fraction comma space if space straight x not equal to 0 end cell row cell space space space space space space space space space straight A space space space space space space space space space space comma space if space straight x equals 0 end cell end table close

Solution
Here space straight f left parenthesis straight x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell fraction numerator 1 minus cos space 8 straight x over denominator 4 straight x squared end fraction comma space if space straight x not equal to 0 end cell row cell space space space space space space space space space straight A space space space space space space space space space space comma space if space straight x equals 0 end cell end table close
space Lt with straight x rightwards arrow 0 below straight f left parenthesis straight x right parenthesis equals Lt with straight x rightwards arrow 0 below fraction numerator 1 minus cos space 8 straight x over denominator 4 straight x squared end fraction equals Lt with straight x rightwards arrow 0 below fraction numerator 2 space sin squared 4 straight x over denominator 4 straight x squared end fraction equals 1 half Lt with straight x rightwards arrow 0 below fraction numerator sin squared 4 straight x over denominator straight x squared end fraction
space space space space space space space space space space space space space space equals 1 half cross times 16 space Lt with straight x rightwards arrow 0 below open parentheses fraction numerator sin space 4 straight x over denominator 4 straight x end fraction close parentheses squared equals 8 cross times left parenthesis 1 right parenthesis squared equals 8 cross times 1 equals 8
Since space straight f left parenthesis straight x right parenthesis space is space continous space at space straight x equals 0
therefore space straight f left parenthesis 0 right parenthesis equals Lt with straight x rightwards arrow 0 below straight f left parenthesis straight x right parenthesis space rightwards double arrow space space space space straight A equals 8.

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