Find the minor of element 6 in the determinant $increment space equals space open vertical bar table row 1 cell space 2 end cell cell space 3 end cell row 4 cell space 5 end cell cell space 6 end cell row 7 cell space 8 end cell cell space 9 end cell end table close vertical bar$

Solution

increment space equals space open vertical bar table row 1 cell space 2 end cell cell space 3 end cell row 4 cell space 5 end cell cell space 6 end cell row 7 cell space 8 end cell cell space 9 end cell end table close vertical bar

Since 6 lies in the second row and third column minor of 6 is M₂3, which is obtained by deleting 2nd row and third column of A.

therefore space space space straight M subscript 23 space equals space open vertical bar table row 1 cell space space space 2 end cell row 7 cell space space space 8 end cell end table close vertical bar space equals space 8 minus 14 space equals space minus 6

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