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Determinants

Question
CBSEENMA12034487

Find the area of the triangle with vertices at the points given in each of the following:
(–2,–3), (3, 2), (–1,–8)

Solution

Let ∆ be the area of the triangle whose vertices are (–2,  –3), (3,  2), (–1,  –8).
therefore space space space space space space space increment space equals space 1 half open vertical bar table row cell negative 2 end cell cell space space space minus 3 end cell cell space space space 1 end cell row 3 cell space space space space space 2 end cell cell space space space 1 end cell row cell negative 1 end cell cell space space minus 8 end cell cell space space space 1 end cell end table close vertical bar
space space space space space space space space space space space space space space space space space equals space 1 half open vertical bar table row cell negative 2 end cell cell space space space space minus 3 end cell cell space space space 1 end cell row 5 cell space space space space space space space 5 end cell cell space space space 0 end cell row 1 cell space space space minus 5 end cell cell space space space 0 end cell end table close vertical bar comma space space by space straight R subscript 2 space rightwards arrow space straight R subscript 2 minus straight R subscript 1 comma space space space straight R subscript 3 space rightwards arrow space straight R subscript 3 space minus straight R subscript 1
space space space space space space space space space space space space space space space space space equals space 1 half open vertical bar table row 5 cell space space space space space space space space space 5 end cell row 1 cell space space space space space space minus 5 end cell end table close vertical bar space equals space 1 half left parenthesis negative 25 minus 5 right parenthesis space equals space minus 15
space space space space space space space space space space space space space space space space space equals space 15 space left parenthesis in space magnitude right parenthesis space sq. space units.

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