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Matrices

Question
CBSEENMA12034302

if space straight A equals space open square brackets table row 1 cell space space space space space 1 end cell cell space space space space 1 end cell row 1 cell space space space space 1 end cell cell space space space 1 end cell row 1 cell space space space space 1 end cell cell space space 1 end cell end table close square brackets comma space prove space that space space space straight A to the power of straight n equals space open square brackets table row cell 3 to the power of straight n minus 1 end exponent end cell cell space space space 3 to the power of straight n minus 1 end exponent end cell cell space space space space 3 to the power of straight n minus 1 end exponent end cell row cell 3 to the power of straight n minus 1 end exponent end cell cell space space space space 3 to the power of straight n minus 1 end exponent end cell cell space space space space 3 to the power of straight n minus 1 end exponent end cell row cell 3 to the power of straight n minus 1 end exponent end cell cell space space space space 3 to the power of straight n minus 1 end exponent end cell cell space space space space 3 to the power of straight n minus 1 end exponent end cell end table close square brackets comma space straight n space element of space straight N.

Solution
Syntax error from line 1 column 16602 to line 1 column 16609.