Question

$Find space straight x space such space that open square brackets table row 1 2 1 end table close square brackets space space open square brackets table row 1 2 0 row 2 0 1 row 1 0 2 end table close square brackets space space open square brackets table row 0 row 2 row straight x end table close square brackets equals 0$

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Solution

open square brackets table row 1 2 1 end table close square brackets space space open square brackets table row 1 2 0 row 2 0 1 row 1 0 2 end table close square brackets space space open square brackets table row 0 row 2 row straight x end table close square brackets equals 0 rightwards double arrow space open square brackets table row cell 1 plus 4 plus 1 end cell cell 2 plus 0 plus 0 end cell cell 0 plus 2 plus 2 end cell end table close square brackets space open square brackets table row 0 row 2 row straight x end table close square brackets equals 0 space space space rightwards double arrow open square brackets table row 6 2 4 end table close square brackets space open square brackets table row 0 row 2 row straight x end table close square brackets equals 0 rightwards double arrow open square brackets table row cell 0 plus end cell cell 4 plus end cell cell 4 straight x end cell end table close square brackets equals open square brackets 0 close square brackets space space space space rightwards double arrow space 4 plus 4 straight x equals 0 space space space space rightwards double arrow space straight x equals negative 1 rightwards double arrow open square brackets table row cell 1 plus 4 plus 1 end cell cell 2 plus 0 plus 0 end cell cell 0 plus 2 plus 2 end cell end table close square brackets space space open square brackets table row 2 row straight x end table close square brackets equals 0 space space rightwards double arrow space space open square brackets table row 6 2 4 end table close square brackets space equals 0 rightwards double arrow open square brackets table row cell 0 plus end cell cell 4 plus end cell cell 4 straight x end cell end table close square brackets equals open square brackets 0 close square brackets space space space space rightwards double arrow space space 4 plus 4 straight x equals 0 space space space space space straight x equals negative 1 therefore space space space space space straight x equals negative 1

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