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Matrices

Question
CBSEENMA12034226

Find space straight y space if space open square brackets table row straight x 1 end table close square brackets space space open square brackets table row 1 0 row cell negative 2 end cell 3 end table close square brackets space space open square brackets table row straight x row 3 end table close square brackets equals 0

Solution
space open square brackets table row straight x 1 end table close square brackets space space open square brackets table row 1 0 row cell negative 2 end cell 3 end table close square brackets space space open square brackets table row straight x row 3 end table close square brackets equals 0
rightwards double arrow open square brackets table row cell straight x minus 2 end cell cell 0 minus 3 end cell end table close square brackets space space open square brackets table row straight x row 3 end table close square brackets equals 0 space space space space space space space space space rightwards double arrow space open square brackets table row cell straight x minus 2 end cell cell negative 3 end cell end table close square brackets space space open square brackets table row straight x row 3 end table close square brackets equals 0
space rightwards double arrow open square brackets table row cell straight x squared minus 2 end cell cell straight x minus 9 end cell end table close square brackets equals space left square bracket 0 right square bracket space space space space space space space space space space space space space space space rightwards double arrow space space straight x squared minus 2 straight x minus 9 equals 0
therefore space space space space space space space straight x equals fraction numerator 2 plus-or-minus square root of 4 plus 36 end root over denominator 2 end fraction equals fraction numerator 2 plus-or-minus square root of 40 over denominator 2 end fraction equals space fraction numerator 2 plus-or-minus 2 square root of 10 over denominator 2 end fraction equals 1 plus-or-minus square root of 10

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