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Vector Algebra

Question
CBSEENMA12034277

Prove by vector method that sin (A – B) = sin A cos B – cos A sin B

Solution
Let OX and OY be two axes and let straight I with hat on top space and space straight j with hat on top be unit vectors along OX and OY respectively.

          Let  OP with rightwards arrow on top space and space OQ with rightwards arrow on top be two vectors such that 
     angle XOP space equals space straight A space and space angle XOQ space space equals space straight B so that
                angle POQ space equals space space straight A space minus space straight B.
        Draw PL space perpendicular space OX comma space space QM space perpendicular space OX.
         Let space straight k with hat on top be the unit vector along z-axis.
         Now,        OP with rightwards arrow on top space equals space OL with rightwards arrow on top space plus space LP with rightwards arrow on top
                                equals space left parenthesis OP space cos space straight A right parenthesis straight i with hat on top space plus space left parenthesis OP space sin space straight A right parenthesis straight j with hat on top                              
and         OQ with rightwards arrow on top space equals space OM with rightwards arrow on top space plus space MQ with rightwards arrow on top
                       equals space left parenthesis OQ space cos space straight B right parenthesis space straight i with hat on top space plus space left parenthesis OQ space sin space straight B right parenthesis space straight j with hat on top
therefore space space space OP with rightwards arrow on top space cross times space OQ with rightwards arrow on top space equals space open square brackets left parenthesis OP space cos space straight A right parenthesis space straight i with hat on top space plus space left parenthesis OP space sin space straight A right parenthesis space straight j with hat on top close square brackets space cross times space open square brackets left parenthesis OQ space cos space straight B right parenthesis straight i with hat on top plus space left parenthesis OQ space sin space straight B right parenthesis space straight j with hat on top close square brackets
                          equals space OP. space OQ space open square brackets left parenthesis cos space straight A right parenthesis space straight i with hat on top space plus space sin space straight A right parenthesis space straight j with hat on top close square brackets space cross times space open square brackets left parenthesis cos space straight B right parenthesis straight i with hat on top space plus space left parenthesis sin space straight B right parenthesis straight j with hat on top close square brackets
equals space OP. space OQ space open square brackets left parenthesis cos space straight A space sin space straight B right parenthesis thin space left parenthesis straight i with hat on top space cross times space straight j with hat on top right parenthesis space plus space left parenthesis sin space straight A space cos space straight B right parenthesis thin space left parenthesis straight j with hat on top space cross times straight i with hat on top space right parenthesis close square brackets
space equals space OP. space OQ space left square bracket cos space straight A space sin space straight B space straight k with hat on top space minus space sin space straight A space cos space straight B space straight k with hat on top right square bracket
space equals space OP. space OQ space left square bracket cos space straight A space sin space straight B space minus space sin space straight A space cos space straight B right square bracket space straight k with hat on top space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space... left parenthesis 1 right parenthesis
Also,   OP with rightwards arrow on top space cross times space OQ with rightwards arrow on top space equals space open vertical bar OP with rightwards arrow on top close vertical bar space open vertical bar OQ with rightwards arrow on top close vertical bar space sin space left parenthesis straight A minus straight B right parenthesis space left parenthesis negative straight k with hat on top right parenthesis
                                         equals space space minus OP. space OQ space sin space left parenthesis straight A minus straight B right parenthesis space straight k with hat on top                                         ...(2)
From (1) and (2), we get
                         cos space straight A space sin space straight B space minus space sin space straight A space cos space straight B space equals space minus sin space left parenthesis straight A minus straight B right parenthesis
therefore space space space space space space space space space space space space space space space space space space   sin left parenthesis straight A minus straight B right parenthesis space equals space sin space straight A space cos space straight B space minus space cos space straight A space sin space straight B.