Question

$If space space straight A equals open square brackets table row 2 3 row 1 cell 2 space end cell end table close square brackets comma space prove space that space straight A to the power of 1 space — space 4 straight A squared space plus space straight A space equals space straight O.$

Name: Wired Faculty - The Best Learning App
Rating: 4.6 (1864 reviews)

Solution

space straight A equals open square brackets table row 2 3 row 1 cell 2 space end cell end table close square brackets therefore space space straight A squared equals space space open square brackets table row 2 3 row 1 cell 2 space end cell end table close square brackets space open square brackets table row 2 3 row 1 cell 2 space end cell end table close square brackets space equals space open square brackets table row cell 4 plus 3 end cell cell 6 plus 6 end cell row cell 2 plus 2 end cell cell 3 plus 4 end cell end table close square brackets equals open square brackets table row 7 12 row 4 7 end table close square brackets space space space space space straight A cubed space equals space straight A squared space straight A space equals space open square brackets table row 7 12 row 4 7 end table close square brackets space space equals space open square brackets table row cell 14 plus 12 end cell cell 21 plus 24 end cell row cell 8 plus 7 end cell cell 12 plus 24 end cell end table close square brackets equals space open square brackets table row 26 45 row 15 26 end table close square brackets space straight L. straight H. straight S. space space space equals space straight A cubed space minus 4 straight A squared space plus straight A space space space space space space space space space space space space space space space space equals space open square brackets table row 26 45 row 15 26 end table close square brackets minus 4 space open square brackets table row 7 12 row 4 7 end table close square brackets space plus space open square brackets table row 2 3 row 1 2 end table close square brackets space space space space space space space space space space space space space space space space equals space open square brackets table row 26 45 row 15 26 end table close square brackets plus space open square brackets table row cell negative 28 end cell cell negative 48 end cell row cell negative 16 end cell cell negative 28 end cell end table close square brackets plus space space open square brackets table row 2 3 row 1 2 end table close square brackets space space space space space space space space space space space space space space space space space equals space open square brackets table row cell 26 minus 28 plus 2 end cell cell 45 minus 48 plus 3 end cell row cell 15 minus 16 plus 1 end cell cell 26 minus 28 plus 2 end cell end table close square brackets space space space equals space open square brackets table row 0 0 row 0 0 end table close square brackets equals 0 space space space space space space space space space space space space space space space space space space space equals space straight R. straight H. straight S therefore space space space straight A cubed minus 4 straight A squared space plus straight A space equals 0

For Daily Free Study Material Join wiredfaculty

Matrices

$If space space straight A equals open square brackets table row 2 3 row 1 cell 2 space end cell end table close square brackets comma space prove space that space straight A to the power of 1 space — space 4 straight A squared space plus space straight A space equals space straight O.$

Some More Questions From Matrices Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Phone Number

Email Address

Loaction