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Vector Algebra

Question
CBSEENMA12034132

Let straight a with rightwards arrow on top comma space straight b with rightwards arrow on top comma space straight c with rightwards arrow on top be three vectors of magnitude 5, 3, 1 respectively. If each one is perpendicular to the sum of other two vectors, prove that open vertical bar straight a with rightwards arrow on top plus straight b with rightwards arrow on top plus straight c with rightwards arrow on top close vertical bar space equals space square root of 35.

Solution
We have
open vertical bar straight a with rightwards arrow on top close vertical bar space equals space 5 comma space space open vertical bar straight b with rightwards arrow on top close vertical bar space equals space 3 comma space space open vertical bar straight c with rightwards arrow on top close vertical bar space equals space 1                             ...(1)
Since straight a with rightwards arrow on top is perpendicular to straight b with rightwards arrow on top plus straight c with rightwards arrow on top,  straight b with rightwards arrow on top is perpendicular to straight c with rightwards arrow on top plus straight a with rightwards arrow on top space and space straight c with rightwards arrow on top is perpendicular to straight a with rightwards arrow on top plus straight b with rightwards arrow on top.
therefore space space space straight a with rightwards arrow on top. space left parenthesis straight b with rightwards arrow on top plus straight c with rightwards arrow on top right parenthesis space equals space 0
                                          ...(2)
       straight b with rightwards arrow on top. space left parenthesis straight c with rightwards arrow on top plus straight a with rightwards arrow on top right parenthesis space equals space 0                                           ...(3)
and  straight c with rightwards arrow on top. space left parenthesis straight a with rightwards arrow on top plus straight b with rightwards arrow on top right parenthesis space equals space 0                                         ...(4)
Now,   open vertical bar straight a with rightwards arrow on top plus straight b with rightwards arrow on top plus straight c with rightwards arrow on top close vertical bar squared space equals space left parenthesis straight a with rightwards arrow on top plus straight b with rightwards arrow on top plus straight c with rightwards arrow on top right parenthesis. space left parenthesis straight a with rightwards arrow on top plus straight b with rightwards arrow on top plus straight c with rightwards arrow on top right parenthesis
                equals space straight a with rightwards arrow on top. space straight a with rightwards arrow on top space plus space straight a with rightwards arrow on top. space left parenthesis straight b with rightwards arrow on top plus straight c with rightwards arrow on top right parenthesis space plus space straight b with rightwards arrow on top. straight b with rightwards arrow on top space plus space straight b with rightwards arrow on top. space left parenthesis straight c with rightwards arrow on top plus straight a with rightwards arrow on top right parenthesis space plus straight c with rightwards arrow on top. straight c with rightwards arrow on top plus straight c with rightwards arrow on top. space left parenthesis straight a with rightwards arrow on top plus straight b with rightwards arrow on top right parenthesis
equals space open vertical bar straight a with rightwards arrow on top close vertical bar squared plus straight a with rightwards arrow on top. space left parenthesis straight b with rightwards arrow on top plus straight c with rightwards arrow on top right parenthesis space plus open vertical bar straight b with rightwards arrow on top close vertical bar squared space plus straight b with rightwards arrow on top. space thin space left parenthesis straight c with rightwards arrow on top plus straight a with rightwards arrow on top right parenthesis space plus space open vertical bar straight c with rightwards arrow on top close vertical bar squared space plus straight c with rightwards arrow on top. space left parenthesis straight a with rightwards arrow on top plus straight b with rightwards arrow on top right parenthesis
space equals space 25 plus 0 plus 9 plus 0 plus 1 plus 0 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space open square brackets because space of space left parenthesis 1 right parenthesis comma space left parenthesis 2 right parenthesis comma space left parenthesis 3 right parenthesis comma space left parenthesis 4 right parenthesis close square brackets
therefore space space space space open vertical bar straight a with rightwards arrow on top plus straight b with rightwards arrow on top plus straight c with rightwards arrow on top close vertical bar squared space equals space 35
therefore space space space space space space open vertical bar straight a with rightwards arrow on top plus straight b with rightwards arrow on top plus straight c with rightwards arrow on top close vertical bar space equals space square root of 35.