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Home > Vector Algebra

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Vector Algebra

Question
CBSEENMA12034106
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Find the angle between the vectors straight a with rightwards arrow on top space equals straight i with hat on top space minus space straight j with hat on top space plus space straight k with hat on top space and straight b with rightwards arrow on top space equals space straight i with hat on top space plus space straight j with hat on top space minus space straight k with hat on top.

Solution
Short Answer
Let straight theta be angle between the vectors
                    straight a with rightwards arrow on top space equals space straight i with hat on top space minus space straight j with hat on top space plus space straight k with hat on top space and space straight b with rightwards arrow on top space equals space straight i with hat on top space plus space straight j with hat on top space minus space straight k with hat on top
Now,      straight a space equals square root of left parenthesis 1 right parenthesis squared plus left parenthesis negative 1 right parenthesis squared plus left parenthesis 1 right parenthesis squared end root space equals space square root of 1 plus 1 plus 1 end root space equals square root of 3
              straight b equals space square root of left parenthesis 1 right parenthesis squared plus left parenthesis 1 right parenthesis squared plus left parenthesis negative 1 right parenthesis squared end root space equals square root of 1 plus 1 plus 1 end root space equals square root of 3
          straight a with rightwards arrow on top. space straight b with rightwards arrow on top space equals space left parenthesis 1 right parenthesis thin space left parenthesis 1 right parenthesis space plus space left parenthesis negative 1 right parenthesis thin space left parenthesis 1 right parenthesis space plus space left parenthesis 1 right parenthesis thin space left parenthesis negative 1 right parenthesis space equals space 1 minus 1 minus 1 space equals negative 1
Now    straight a with rightwards arrow on top. space straight b with rightwards arrow on top space equals space straight a space straight b space cos space straight theta space space space rightwards double arrow space space space space minus 1 space equals space left parenthesis square root of 3 right parenthesis thin space left parenthesis square root of 3 right parenthesis space cos space straight theta
therefore space space space space space 3 space cos space straight theta space equals space minus 1 space space space space space space space space space or space space space cos space straight theta space equals space minus 1 third
therefore space space space space space space space space space straight theta space equals space cos to the power of negative 1 end exponent space open parentheses negative 1 third close parentheses.

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