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Vector Algebra

Question
CBSEENMA12034038

If straight a with rightwards arrow on top comma space straight b with rightwards arrow on top comma space stack straight c comma with rightwards arrow on top straight d with rightwards arrow on top are any four vectors in 3 - dimensional space with the same initial point and such that 3 space straight a with rightwards arrow on top space space minus space 2 space straight b with rightwards arrow on top space plus space straight c with rightwards arrow on top space minus space 2 space straight d with rightwards arrow on top space equals space 0 with rightwards arrow on top comma space show that terminals, A, B, C, D of these vectors are coplanar. Find the point at which AC and BD meet. Find the ratio in which P divides AC and BD.

Solution

Since,   3 space straight a with rightwards arrow on top space minus space 2 space straight b with rightwards arrow on top space plus space straight c with rightwards arrow on top space minus space 2 space straight d with rightwards arrow on top space equals space 0 with rightwards arrow on top
therefore space space space space 3 space straight a with rightwards arrow on top space plus space straight c with rightwards arrow on top space equals space 2 space straight b with rightwards arrow on top space plus space 2 space straight d with rightwards arrow on top
 rightwards double arrow space space space fraction numerator 3 space straight a with rightwards arrow on top space plus space straight c with rightwards arrow on top over denominator 4 end fraction space equals space fraction numerator 2 space straight b with rightwards arrow on top space plus space 2 space straight d with rightwards arrow on top over denominator 4 end fraction space space space rightwards double arrow space space space space space fraction numerator 3 space straight a with rightwards arrow on top space plus space straight c with rightwards arrow on top over denominator 3 plus 1 end fraction space equals space fraction numerator straight b with rightwards arrow on top plus straight d with rightwards arrow on top over denominator 2 end fraction
∴    P.V. of point dividing AC in the ratio 1 : 3 is the same as the P.V. of mid-point of BD.
∴    AC and BD intersect at P whose P.V. is fraction numerator 3 straight a with rightwards arrow on top space plus space straight c with rightwards arrow on top over denominator 4 end fraction space or space space fraction numerator straight b with rightwards arrow on top space plus space straight d with rightwards arrow on top over denominator 2 end fraction. This point P divides AC in the ratio 3:1 and BD in the ratio 1:1.