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Home > Vector Algebra

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Vector Algebra

Question
CBSEENMA12034002
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Find the condition that the vectors straight a with rightwards arrow on top space equals space straight k space straight i with hat on top space plus space 3 space straight j with hat on top space and space straight b with rightwards arrow on top space equals space 4 space straight i with hat on top space plus space straight k space straight j with hat on top comma space space left parenthesis straight k space not equal to space 0 right parenthesis are parallel.

Solution
Long Answer

Here,   straight a with rightwards arrow on top space equals space straight k straight i with hat on top space plus space 3 straight j with hat on top comma space space straight b with rightwards arrow on top space equals space 4 straight i with hat on top space plus space space straight k straight j with hat on top
Let straight a with rightwards arrow on top space and space straight b with rightwards arrow on top   be parallel..
  therefore space space   there exists a non-zero scalar straight lambda such that
               straight a with rightwards arrow on top space equals space straight lambda straight b with rightwards arrow on top
therefore space space straight k space straight i with hat on top space plus space 3 space straight j with hat on top space equals space 4 space straight lambda space straight i with hat on top space plus space straight lambda space straight k space straight j with hat on top
therefore space space space left parenthesis straight k space minus space 4 space straight lambda right parenthesis space straight i with hat on top space plus space left parenthesis 3 space minus space straight k space straight lambda right parenthesis space straight j with hat on top space equals space 0 with rightwards arrow on top
rightwards double arrow space space space space straight k space minus space 4 space straight lambda space equals space 0 comma space space space space 3 space space minus space straight k space straight lambda space equals space 0
rightwards double arrow space space space space space space space space space space space space space straight lambda space equals straight k over 4 comma space space space space straight lambda space equals space 3 over straight k
Equating values of straight lambda comma we get,
                      straight k over 4 space equals space 3 over straight k space space space or space space space straight k squared space equals space 4 space cross times space 3 space equals space 12
which is required condition. 
             


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