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Home > Vector Algebra

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Vector Algebra

Question
CBSEENMA12034093
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Find open vertical bar straight a with rightwards arrow on top minus straight b with rightwards arrow on top close vertical bar squared if open vertical bar straight a with rightwards arrow on top close vertical bar space equals space 3 comma space space space space open vertical bar straight b with rightwards arrow on top close vertical bar space equals space 4 space and space straight a with rightwards arrow on top. space straight b with rightwards arrow on top space equals space 1.

Solution
Short Answer

Here open vertical bar straight a with rightwards arrow on top close vertical bar space equals space 3 comma space space space space open vertical bar straight b with rightwards arrow on top close vertical bar space equals space 4 comma space space space space straight a with rightwards arrow on top. space straight b with rightwards arrow on top space equals space 1                             ...(1)
Now,         open vertical bar straight a with rightwards arrow on top space minus space straight b with rightwards arrow on top close vertical bar squared space space equals space left parenthesis straight a with rightwards arrow on top space minus space straight b with rightwards arrow on top right parenthesis squared space equals space straight a with rightwards arrow on top squared plus space straight b with rightwards arrow on top squared space minus space 2 space straight a with rightwards arrow on top. space straight b with rightwards arrow on top space equals space open vertical bar straight a with rightwards arrow on top close vertical bar squared space plus space open vertical bar straight b with rightwards arrow on top close vertical bar squared space minus space 2 space straight a with rightwards arrow on top. space straight b with rightwards arrow on top
                            equals space 9 plus 16 minus 2 space equals space 23 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space left square bracket because space of space left parenthesis 1 right parenthesis right square bracket


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