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Vector Algebra

Question
CBSEENMA12034074

Find the angle between two vectors straight a with rightwards arrow on top space and space straight b with rightwards arrow on top with magnitudes square root of 3 space and space 2 comma space respectively comma space and space that space space straight a with rightwards arrow on top. space straight b with rightwards arrow on top space equals space square root of 6.

Solution

Here straight a equals space square root of 3 comma space space straight b space equals space 2 comma space space straight a with rightwards arrow on top space. space straight b with rightwards arrow on top space equals space square root of 6
Let straight theta be the angle between and straight a with rightwards arrow on top space and space straight b with rightwards arrow on top.
Now,   straight a with rightwards arrow on top. space straight b with rightwards arrow on top space equals space ab space cos space straight theta space space space space space space space space space space space space space space space rightwards double arrow space space space space square root of 6 space equals space left parenthesis square root of 3 right parenthesis thin space left parenthesis 2 right parenthesis space cos space straight theta
rightwards double arrow space space space cos space straight theta space equals space fraction numerator square root of 6 over denominator 2 square root of 3 end fraction space equals space fraction numerator 1 over denominator square root of 2 end fraction space space space space rightwards double arrow space space space space straight theta space equals space 45 degree