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Vector Algebra

Question
CBSEENMA12034050

If P and Q are the mid-points of the sides AB and CD of a parallelogram ABCD, prove that DP and BQ cut the diagonal AC in its points of trisection which are also the points of trisection of DP and BQ respectively.

Solution
Take A as origin. Let straight b with rightwards arrow on top space and space straight d with rightwards arrow on top be position vectors of B and D respectively such that
AB with rightwards arrow on top space equals space straight b with rightwards arrow on top comma space space AD with rightwards arrow on top space equals space straight d with rightwards arrow on top

Now position vector of P, mid-point of AB, is fraction numerator straight d with rightwards arrow on top over denominator 2 end fraction.
Also,    AQ with rightwards arrow on top space equals space AD with rightwards arrow on top space plus space DQ with rightwards arrow on top space equals space AD with rightwards arrow on top space space plus space 1 half DC with rightwards arrow on top space equals AD with rightwards arrow on top space plus space 1 half AB with rightwards arrow on top space equals space straight d with rightwards arrow on top space plus space 1 half straight b with rightwards arrow on top
therefore  position vector of Q is straight d with rightwards arrow on top space plus space fraction numerator straight b with rightwards arrow on top over denominator 2 end fraction
              AC with rightwards arrow on top space equals space AB with rightwards arrow on top space plus space BC with rightwards arrow on top space equals space AB with rightwards arrow on top space plus space AD with rightwards arrow on top space equals space straight b with rightwards arrow on top plus straight d with rightwards arrow on top
Let E divide AC in the ratio 1 : 2 and F divide AC in the ratio 2 : 1
therefore position vector of E is fraction numerator 1 left parenthesis straight b with rightwards arrow on top plus straight d with rightwards arrow on top right parenthesis space plus space 2 left parenthesis stack 0 right parenthesis with rightwards arrow on top over denominator 1 plus 2 end fraction space equals space fraction numerator straight b with rightwards arrow on top space plus space straight d with rightwards arrow on top over denominator 3 end fraction
Position vector of point dividing PD in the ratio 1:2 is fraction numerator left parenthesis 1 right parenthesis space straight d with rightwards arrow on top space plus left parenthesis 2 right parenthesis open parentheses begin display style fraction numerator straight b with rightwards arrow on top over denominator 2 end fraction end style close parentheses over denominator 1 plus 2 end fraction space equals fraction numerator straight b with rightwards arrow on top plus straight d with rightwards arrow on top over denominator 3 end fraction
Position vector of straight F with rightwards arrow on top is fraction numerator 2 left parenthesis straight b with rightwards arrow on top plus straight d with rightwards arrow on top right parenthesis space plus space 1 left parenthesis 0 with rightwards arrow on top right parenthesis over denominator 1 plus 2 end fraction space equals space fraction numerator 2 straight b with rightwards arrow on top plus 2 straight d with rightwards arrow on top over denominator 3 end fraction
Position vector of point dividing BQ in the ratio 2 : 1 is fraction numerator 2 space open parentheses straight d with rightwards arrow on top plus begin display style fraction numerator straight b with rightwards arrow on top over denominator 2 end fraction end style close parentheses plus space 1 left parenthesis straight b with rightwards arrow on top right parenthesis over denominator 2 plus 1 end fraction equals space fraction numerator 2 straight b with rightwards arrow on top space plus space 2 straight d with rightwards arrow on top over denominator 3 end fraction
 ∴    DP and BQ cut diagonal AC in its points of trisection which are also the points of trisection of DP and BQ respectively.