+91-8076753736 support@wiredfaculty.com
logo
logo

Sponsor Area

Vector Algebra

Question
CBSEENMA12032995
Wired Faculty App

Solve dy over dx space equals fraction numerator 3 straight x squared over denominator 1 plus straight y squared end fraction

Solution
The given differential equation is
                      dy over dx equals fraction numerator 3 straight x squared over denominator 1 plus 3 straight y squared end fraction
Separating the variables, we get,
                  left parenthesis 1 plus 3 straight y squared right parenthesis space dy space equals space 3 straight x squared dx
Integrating,   integral left parenthesis 1 plus 3 straight y squared right parenthesis space dy space equals space integral 3 straight x squared dx
therefore space space space space integral 1 space dy space plus space 3 space integral straight y squared space dy space equals space 3 integral straight x squared space dx
therefore                                straight y plus straight y cubed space equals straight x cubed plus straight c comma space space space which space is space the space required space solution.

Some More Questions From Vector Algebra Chapter

Determine order and degree (if defined) of differential equations:
y' + y = ex

Determine order and degree (if defined) of differential equations:
y'' + (y')2 + 2 y = 0

Determine order and degree (if defined) of differential equations:
y″ + 2y′ + sin y = 0

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation