-->

Vector Algebra

Question
CBSEENMA12032994

Solve straight x to the power of 5 dy over dx space equals space minus straight y to the power of 5

Solution

The given differential equation is
                           straight x to the power of 5 dy over dx equals negative straight y to the power of 5 space space space space or space space space space space dy over dx space equals space minus straight y to the power of 5 over straight x to the power of 5
Separating the variables, we get,
                               1 over straight y to the power of 5 dy space equals space minus 1 over straight x to the power of 5 dx
Integrating,    integral 1 over straight y to the power of 5 dy space equals space minus integral 1 over straight x to the power of 5 dx space space or space space space integral straight y to the power of negative 5 end exponent dy space equals negative integral straight x to the power of negative 5 end exponent dx
 therefore space space space space space space fraction numerator straight y to the power of negative 4 end exponent over denominator negative 4 end fraction space equals space minus fraction numerator straight x to the power of negative 4 end exponent over denominator negative 4 end fraction plus straight c apostrophe space space space space space or space space space fraction numerator 1 over denominator negative 4 straight y to the power of 4 end fraction space equals space fraction numerator 1 over denominator 4 straight x to the power of 4 end fraction plus straight c apostrophe
or            1 over straight x to the power of 4 plus 1 over straight y to the power of 4 space equals space minus 4 straight c apostrophe
or            straight x to the power of negative 4 end exponent plus straight y to the power of negative 4 end exponent space equals space straight c comma space space where space straight c space equals space minus 4 straight c apostrophe.