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Vector Algebra

Question
CBSEENMA12032967

Determine the differential equation that will represent the family of all circles having centres on the x-axis and radius unity.

Solution
Let centre on x-axis be (a. 0). Also radius = 1
∴    the equation of the family of circles is
             open parentheses straight x minus straight a close parentheses squared plus left parenthesis straight y minus 0 right parenthesis squared space equals space 1 space space space space space space space space space space space space or space space space space space space left parenthesis straight x minus straight a right parenthesis squared plus straight y squared space equals 1 space                 ...(1)
Differentiating w.r.t x, we get,
             2 left parenthesis straight x minus straight a right parenthesis plus 2 straight y dy over dx space equals 0             or      straight x minus straight a space equals space minus straight y dy over dx
Putting this value of x - a in (1), we get,
                                open parentheses negative straight y dy over dx close parentheses squared plus straight y squared space equals space 1 space space space space space space space space space space space space space space space space space space space space or space space space space space space space straight y squared open parentheses dy over dx close parentheses squared plus straight y squared space equals space 1
which is required differential equation.