If $straight A equals open square brackets table row 1 2 3 row 2 3 1 end table close square brackets space and space straight B equals open square brackets table row 3 cell negative 1 end cell 3 row cell negative 1 end cell 0 2 end table close square brackets$ , then find 2A - B.

Solution

straight A equals open square brackets table row 1 2 3 row 2 3 1 end table close square brackets. space straight B equals open square brackets table row 3 cell negative 1 end cell 3 row cell negative 1 end cell 0 2 end table close square brackets therefore space space space space space 2 A equals open square brackets table row 2 4 6 row 4 6 2 end table close square brackets therefore space space space 2 A minus B equals open square brackets table row 2 4 6 row 4 6 2 end table close square brackets minus open square brackets table row 3 cell negative 1 end cell 3 row cell negative 1 end cell 0 2 end table close square brackets space space space space space space space space space space space space space space space equals open square brackets table row 2 4 6 row 4 6 2 end table close square brackets plus open square brackets table row cell negative 3 end cell 1 cell negative 3 end cell row 1 0 cell negative 2 end cell end table close square brackets space space space space space space space space space space space space space space space equals open square brackets table row cell 2 minus 3 end cell cell 4 plus 1 end cell cell 6 minus 3 end cell row cell 4 plus 1 end cell cell 6 plus 0 end cell cell 2 minus 2 end cell end table close square brackets equals open square brackets table row cell negative 1 end cell 5 3 row 5 6 0 end table close square brackets

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