If $straight A equals open square brackets table row 2 4 row 3 2 end table close square brackets space and space straight B equals open square brackets table row cell space 1 end cell 3 row cell negative 2 space end cell 5 end table close square brackets$ then find A – B.

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Solution

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straight A equals open square brackets table row 2 4 row 3 2 end table close square brackets space and space straight B equals open square brackets table row 1 3 row cell negative 2 end cell 5 end table close square brackets therefore space space space straight A minus straight B equals open square brackets table row 2 4 row 3 2 end table close square brackets minus open square brackets table row 1 3 row cell negative 2 end cell 5 end table close square brackets equals open square brackets table row 2 4 row 3 2 end table close square brackets space plus open square brackets table row cell negative 1 end cell cell negative 3 end cell row 2 cell negative 5 end cell end table close square brackets space space space space space space space space space space space space space equals straight A space open square brackets table row cell 2 minus 1 end cell cell 4 minus 3 end cell row cell 3 plus 2 end cell cell 2 minus 5 end cell end table close square brackets equals open square brackets table row 1 cell space space space 1 end cell row 5 cell negative 3 end cell end table close square brackets

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