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Matrices

Question
CBSEENMA12032903

Which of the given values of x and y make the following pair of matrices equal 

open square brackets table row cell 3 straight x plus 7 end cell 5 row cell straight y plus 1 end cell cell 2 minus 3 straight x end cell end table close square brackets. open square brackets table row 0 cell straight y minus 2 end cell row 8 4 end table close square brackets
  • straight x equals fraction numerator negative 1 over denominator 3 end fraction comma space space straight y space equals 7
  • Not possible to find

  • straight y equals 7 comma space space space straight x equals fraction numerator negative 2 over denominator 3 end fraction
  • straight x equals fraction numerator negative 1 over denominator 3 end fraction comma space space straight y space equals fraction numerator negative 2 over denominator 3 end fraction

Solution

B.

Not possible to find

We are given that 
open square brackets table row cell 3 straight x plus 7 end cell 5 row cell straight y plus 1 end cell cell 2 minus 3 straight x end cell end table close square brackets. open square brackets table row 0 cell straight y minus 2 end cell row 8 4 end table close square brackets

By definition of equality of matrices.
3.x + 7 = 0. 5-= y – 2. y + I = 8, 2 – 3 .r = 4
therefore space space space space space space space space straight x equals 7 over 3 comma space space space straight y equals 7 comma space space space straight x equals negative 2 over 3
∴ (B) is correct answer.