If $open square brackets table row cell straight x minus straight y end cell straight z row cell 2 straight x minus straight y end cell straight w end table close square brackets equals open square brackets table row cell negative 1 end cell 4 row 0 5 end table close square brackets$ find .x. y. z .w.

Solution

We are given that
$open square brackets table row cell straight x minus straight y end cell straight z row cell 2 straight x minus straight y end cell straight w end table close square brackets equals open square brackets table row cell negative 1 end cell 4 row 0 5 end table close square brackets$

From the definition of equality of matrices, we have
x –y = –1    ..(I)
2.x–y=0    ...(2)
z = 4    ...(3)
w = 5     ..(4)
Subtracting (1) from (2). we get,
x= 1
∴from (1). I -y = –l ⇒ y = 2
∴.x – 1. y = 2. z =-4. w- = 5

Some More Questions From Matrices Chapter

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Matrices

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