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Vector Algebra

Question
CBSEENMA12032877

In the following, verify that the given functions, (explicit or implicit) is a solution of the corresponding differential equation:
straight y space equals space square root of 1 plus straight x squared end root               :   straight y apostrophe space equals space fraction numerator xy over denominator 1 plus straight x squared end fraction

Solution

               straight y space equals space square root of 1 plus straight x squared end root                                                      ...(1)
therefore          straight y apostrophe space equals space fraction numerator 2 straight x over denominator 2 square root of 1 plus straight y squared end root end fraction space space or space space space straight y apostrophe space equals space fraction numerator straight x over denominator square root of 1 plus straight x squared end root end fraction               ...(2)
        R.H.S. = fraction numerator xy over denominator 1 plus straight x squared end fraction space equals space fraction numerator straight x square root of 1 plus straight x squared end root over denominator 1 plus straight x squared end fraction                            open square brackets because space space of space space left parenthesis 1 right parenthesis close square brackets
                   equals space fraction numerator straight x over denominator square root of 1 plus straight x squared end root end fraction space equals straight y apostrophe                                        open square brackets because space of space left parenthesis 2 right parenthesis close square brackets
                   equals space straight L. straight H. straight S.
therefore space space space straight y space equals space square root of 1 plus straight x squared end root is a solution of straight y apostrophe space equals space fraction numerator xy over denominator 1 plus straight x squared end fraction