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Vector Algebra

Question

The degree of the differential equation $open parentheses fraction numerator straight d squared straight y over denominator dx squared end fraction close parentheses cubed plus open parentheses dy over dx close parentheses squared plus sin open parentheses dy over dx close parentheses plus 1 space space equals space 0$ is

3

2

1

not defined

Solution

not defined

The given differential equation is

open parentheses fraction numerator straight d squared straight y over denominator dx squared end fraction close parentheses cubed plus open parentheses dy over dx close parentheses squared plus sin open parentheses dy over dx close parentheses plus 1 space equals space 0

Since the differential equation is not a polynomial equation in its derivatives
∴ its degree is not defined