+91-8076753736[email protected]
logo
logo
-->

Vector Algebra

Question
CBSEENMA12032854
Wired Faculty App

Find the order and degree of the equation y = px + square root of straight a squared straight p squared plus straight b squared end root when straight p space equals space dy over dx.
State also if this is linear or non-linear.

Solution

The given equation is
                straight y equals px plus square root of straight a squared straight p squared plus straight b squared end root space space space or space space space space space space space straight y minus straight p space straight x space space equals square root of straight a squared straight p squared plus straight b squared end root
or             left parenthesis straight y minus px right parenthesis squared space equals straight a squared straight p squared plus straight b squared      or       straight y squared plus straight p squared straight x squared space minus space 2 space pxy space equals straight a squared straight p squared plus straight b squared
or            straight y squared plus straight x squared open parentheses dy over dx close parentheses squared minus 2 xy dy over dx space equals space straight a squared open parentheses dy over dx close parentheses squared plus straight b squared
It is of order 1, degree 2 and non-linear

Some More Questions From Vector Algebra Chapter

Determine order and degree (if defined) of differential equations:
y' + y = ex

Determine order and degree (if defined) of differential equations:
y'' + (y')2 + 2 y = 0

Determine order and degree (if defined) of differential equations:
y″ + 2y′ + sin y = 0

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation