In the matrix $straight A equals open square brackets table row 2 5 19 cell negative 7 end cell row 35 cell negative 2 end cell cell 5 over 12 end cell 12 row cell square root of 5 end cell 1 cell negative 5 end cell 17 end table close square brackets. space Write$
(i) The order of the matrix
(ii) The number of elements,
(iii) Write the elements a₁₃,a₂₁ a₃₃ a₂₄’ a₂₃

Solution

Here

straight A equals left parenthesis straight a subscript straight i right parenthesis equals open square brackets table row 2 5 19 cell negative 7 end cell row 35 cell negative 2 end cell cell 5 over 12 end cell 12 row cell square root of 5 end cell 1 cell negative 5 end cell 17 end table close square brackets. space Write

( i) Now A has 3 rows and 4 columns and so A is of order 3 x 4.

(ii) Number of elements = 3 x 4 = 12

(iii) a₁₃, =- 19., a₂₁ =35, a₃₃ = 5, J₂₄ = 12, a₂₃ $equals 5 over 2$

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