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Vector Algebra

Question
CBSEENMA12032834
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Determine order and degree (if defined) of differential equations:
open parentheses ds over dt close parentheses to the power of 4 plus 3 straight s fraction numerator straight d squared straight s over denominator dt squared end fraction equals 0

Solution
The given differential equation is
open parentheses ds over dt close parentheses to the power of 4 plus 3 straight s fraction numerator straight d squared straight s over denominator dt squared end fraction equals space 0
The highest order derivative present in the differential equation is fraction numerator straight d squared straight s over denominator dt squared end fraction
∴  its order is 2
The highest power raised to fraction numerator straight d squared straight s over denominator dt squared end fraction is one, so its degree is 1.

Some More Questions From Vector Algebra Chapter

Determine order and degree (if defined) of differential equations:
y' + y = ex

Determine order and degree (if defined) of differential equations:
y'' + (y')2 + 2 y = 0

Determine order and degree (if defined) of differential equations:
y″ + 2y′ + sin y = 0

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