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Inverse Trigonometric Functions

Question

$cos to the power of negative 1 end exponent open parentheses cos fraction numerator 7 space straight pi over denominator 6 end fraction close parentheses space$ is equal to
$fraction numerator 7 straight pi over denominator 6 end fraction$
$fraction numerator 5 straight pi over denominator 6 end fraction$
$straight pi over 3$
$straight pi over 6$

Solution

fraction numerator 5 straight pi over denominator 6 end fraction