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Vector Algebra

Question
CBSEENMA12032811

Smaller area enclosed by the circle x2 + y2 = 4 and the line x + y = 2 is
Choose the correct answer.
or
Draw the rough sketch and find the area of the region:
{(x, y): x2 + y2 < 4, x + y > 2}.  

  • 2 space left parenthesis straight pi space minus space 2 right parenthesis
  • straight pi space minus 2
  • 2 straight pi minus 1
  • left parenthesis 2 straight pi plus 2 right parenthesis

Solution

B.

straight pi space minus 2

The equation of circle is
                               straight x squared plus straight y squared space equals space 4                ...(1)
Its centre is O(0, 0) and radius OA = OB = 2
The equation of line is
                                x + y = 2  ....(2)
or    straight x over 2 plus straight y over 2 space equals 1
therefore    line passes through A(2, 0),  B(0, 2).
Required area  = area of circle in first quadrant - area increment OAB.
                          equals space integral subscript 0 superscript 2 square root of 4 minus straight x squared space space end root space dx space minus space integral subscript 0 superscript 2 left parenthesis 2 minus straight x right parenthesis space dx                  open square brackets because space of space left parenthesis 1 right parenthesis comma space left parenthesis 2 right parenthesis close square brackets
                          equals space integral subscript 0 superscript 2 square root of left parenthesis 2 right parenthesis squared minus straight x squared end root space dx space minus space integral subscript 0 superscript 2 left parenthesis 2 minus straight x right parenthesis space dx
                           equals space open square brackets straight x over 2 square root of left parenthesis 2 right parenthesis squared minus straight x squared end root plus fraction numerator left parenthesis 2 right parenthesis squared over denominator 2 end fraction sin to the power of negative 1 end exponent straight x over 2 close square brackets subscript 0 superscript 2 space minus space open square brackets 2 straight x minus straight x squared over 2 close square brackets subscript 0 superscript 2
equals space open square brackets 2 over 2 square root of 4 minus 4 end root plus 4 over 2 sin to the power of negative 1 end exponent 1 close square brackets space minus space open square brackets 0 plus 4 over 2 sin to the power of negative 1 end exponent 0 close square brackets space minus space open square brackets open parentheses 4 minus 4 over 2 close parentheses minus left parenthesis 0 minus 0 right parenthesis close square brackets
equals space open parentheses 0 plus 4 over 2 cross times straight pi over 2 close parentheses minus left parenthesis 0 plus 2 cross times 0 right parenthesis space minus space 2 plus 0 space equals space straight pi space minus space 2
                   

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