Area of the region bounded by the curve y² = 4 x, y-axis and the line y = 3 is

2

$9 over 4$
$9 over 3$
$9 over 4$

Solution

9 over 4

The equation of curve is
y² = 4.x
We are to find the area bounded by the curve $straight y squared space equals space 4 straight x comma space space straight y minus axis space and space the space line space straight y space equals space 3.$
Required area = $integral subscript 0 superscript 3 straight x space dy space equals space integral subscript 0 superscript 3 straight y squared over 4 dy$
$equals space 1 fourth integral subscript 0 superscript 3 straight y squared space dy space space equals 1 fourth open square brackets straight y cubed over 3 close square brackets subscript 0 superscript 3 equals space 1 over 12 open square brackets straight y cubed close square brackets subscript 0 superscript 3 space equals space 1 over 12 left parenthesis 27 minus 0 right parenthesis equals space 27 over 12 space equals 9 over 4$

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Vector Algebra

Area of the region bounded by the curve y² = 4 x, y-axis and the line y = 3 is

2

$9 over 4$
$9 over 3$
$9 over 4$

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For Daily Free Study Material Join wiredfaculty

Vector Algebra

Area of the region bounded by the curve y2 = 4 x, y-axis and the line y = 3 is 2

Some More Questions From Vector Algebra Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Area of the region bounded by the curve y² = 4 x, y-axis and the line y = 3 is

2

$9 over 4$
$9 over 3$
$9 over 4$