Question
Using integration, find the area of the triangle ABC whose vertices have coordinates A (3, 0), B(4, 6) and C (6, 2).
Solution
The given vertices are A (3, 0), B (4, 6), C (6, 2). The equation of AB is
or 
or 
...(1)
The equation of BC is
or 
or 
or 
...(2)
The equation of CA is
or 
or 
...(3)
From B. C draw BM. CN ⊥ s on x-axis.
Required area = Area of ∆ AMB + Area of trap. MNCB - area of ∆ANC
