Question
Using integration, find the area of the region bounded by the triangle whose vertices are (-1, 1), (0, 5) and (3, 2).
Solution
Let A(-1, 1), B(0, 5), C(3, 2) be the vertices of the given triangle.
The equation of AB is
or y = 4x + 5 ...(1)
The equation of BC is
or ...(2)
The equation of CA is
or
Required area = Area of ∆ ABC
= Area of region AMOB + area of region BONC - area of region AMNC