-->

Vector Algebra

Question
CBSEENMA12032717

Find the area of the region bounded by the line y = 3 x + 2, the x-axis and the ordinates x = - 1 and x = 1.

Solution

The equation of given line is
y = 3 x + 2    ...(1)
Consider the lines
x = -1    ...(2)
and    x = 1    ...(3)
Line (1) meets x-axis where y = 0

therefore  putting y = 0 in (1), we get,
       0 space equals space 3 straight x plus 2 space space space or space space straight x space space equals space minus 2 over 3
therefore line (1) meets x-axis in straight A open parentheses negative 2 over 3 comma space 0 close parentheses
Let line (1) meet lines (2) and (3) in B and D respectively. From B, draw BC ⊥ x-axis and from D, draw DE ⊥ x-axis.
Required area = Area of region ACBA + area of region ADEA
equals space open vertical bar integral subscript negative 1 end subscript superscript fraction numerator negative 2 over denominator 3 end fraction end superscript left parenthesis 3 straight x plus 2 right parenthesis space dx close vertical bar space plus space integral subscript negative 2 over 3 end subscript superscript 1 left parenthesis 3 straight x plus 2 right parenthesis space dx
equals space open vertical bar open square brackets fraction numerator 3 straight x squared over denominator 2 end fraction plus 2 straight x close square brackets subscript negative 1 end subscript superscript negative 2 over 3 end superscript close vertical bar space plus space open square brackets fraction numerator 3 straight x squared over denominator 2 end fraction plus 2 straight x close square brackets subscript negative 2 over 3 end subscript superscript 1
equals space open vertical bar open curly brackets 3 over 2 minus open parentheses negative 2 over 3 close parentheses squared plus 2 space open parentheses negative 2 over 3 close parentheses close curly brackets space minus space open curly brackets 3 over 2 left parenthesis negative 1 right parenthesis squared plus 2 left parenthesis negative 1 right parenthesis close curly brackets close vertical bar
space space space space space space space space space space space space space space space space space
                                                          plus open square brackets 3 over 2 left parenthesis 1 right parenthesis squared plus 2 left parenthesis 1 right parenthesis close square brackets space minus space open square brackets 3 over 2 open parentheses negative 2 over 3 close parentheses squared plus 2 open parentheses negative 2 over 3 close parentheses close square brackets
equals space open vertical bar open parentheses 2 over 3 minus 4 over 3 close parentheses minus open parentheses 3 over 2 minus 2 close parentheses close vertical bar plus open parentheses 3 over 2 plus 2 close parentheses minus open parentheses 2 over 3 minus 4 over 3 close parentheses space equals space open vertical bar negative 2 over 3 plus 1 half close vertical bar plus open parentheses 7 over 2 plus 2 over 3 close parentheses
equals space open vertical bar negative 1 over 6 close vertical bar plus 25 over 6 space equals space 1 over 6 plus 25 over 6 equals space 26 over 6 equals space 13 over 3 space sq. space units.

Some More Questions From Vector Algebra Chapter