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Vector Algebra

Question
CBSEENMA12032713

Find the area of the region bounded by the curves y = x2 + 2, y = x, x = 0 and x = 3.

Solution

We are to find the area of the region bounded by the curves
y = x2 + 2,
y = x,
x = 0
and x = 3
Now y = x2 + 2 is an upward parabola with vertex (0, 2).
y = x is a straight line passing through the origin,
(3, 3) and lies below the parabola.

Now area bounded by the parabola, above the x-axis and ordinates x = 0, x = 3
equals space integral subscript 0 superscript 3 left parenthesis straight x squared plus 2 right parenthesis space dx space equals space open square brackets straight x cubed over 3 plus 2 straight x close square brackets subscript 0 superscript 3 space equals space open parentheses 27 over 3 plus 6 close parentheses space minus space left parenthesis 0 plus 0 right parenthesis space equals space 15
Area bounded by the line y = x, above the x-axis and ordinates x = 0, x = 3
                   equals space integral subscript 0 superscript 3 straight x space dx space equals space open square brackets straight x squared over 2 close square brackets subscript 0 superscript 3 space equals space 9 over 2 minus 0 space equals space 9 over 2
therefore space space required space area space space equals space 15 space minus space 9 over 2 space equals space 21 over 2 space sq. space units. space

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