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Vector Algebra

Question
CBSEENMA12032704

Draw a graph of straight x squared over 9 plus straight y squared over 25 space equals space 1 and evaluate area bounded by it.

Solution

The equation of ellipse is
                 straight x squared over 9 plus straight y squared over 25 space equals space 1
or                straight y squared over 25 space equals space 1 minus straight x squared over 9
or                 straight y squared space equals space 25 over 9 left parenthesis 9 minus straight x squared right parenthesis
therefore space space space space space straight y space equals space 5 over 3 square root of 9 minus straight x squared end root                     ...(1)
(in the first quadrant)
The ellipse is symmetrical about both the axes.
∴ required area = 4 (area AOB)
equals space 4 integral subscript 0 superscript 3 straight y space dx space equals space 4 integral subscript 0 superscript 3 5 over 3 square root of 9 minus straight x squared end root space dx                                open square brackets because space of space left parenthesis 1 right parenthesis close square brackets space space
equals space 20 over 3 integral square root of left parenthesis 3 right parenthesis squared minus straight x squared end root space dx space equals space 20 over 3 open square brackets fraction numerator straight x square root of 9 minus straight x squared end root over denominator 2 end fraction plus fraction numerator left parenthesis 3 right parenthesis squared over denominator 2 end fraction sin to the power of negative 1 end exponent open parentheses straight x over 3 close parentheses close square brackets subscript 0 superscript 3
equals space 20 over 3 open square brackets open parentheses fraction numerator 3 square root of 9 minus 9 end root over denominator 2 end fraction plus 9 over 2 sin to the power of negative 1 end exponent 1 close parentheses minus open parentheses 0 plus 9 over 2 sin to the power of negative 1 end exponent 0 close parentheses close square brackets
equals space 20 over 3 open square brackets open parentheses 0 plus 9 over 2 cross times straight pi over 2 close parentheses minus left parenthesis 0 plus 0 right parenthesis close square brackets space equals space 20 over 3 cross times fraction numerator 9 straight pi over denominator 4 end fraction space equals space 15 space straight pi space sq. space units.

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