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Vector Algebra

Question
CBSEENMA12032698

The area between x = y2 and x = 4 is divided into two equal parts by the line x = a, find the value of a.

Solution

The equation of parabola is y2 = x
From the given condition, area OAP under y2 = x between x = 0 and x = a = area ABQP under y2 = x between x = a and x = 4.
therefore space space space integral subscript 0 superscript straight a straight y space dx space equals space integral subscript straight a superscript 4 space straight y space dx
rightwards double arrow space space integral subscript 0 superscript straight a square root of straight x space dx space equals space integral subscript straight a superscript 4 square root of straight x space dx
rightwards double arrow space space integral subscript 0 superscript straight a straight x to the power of 1 half end exponent dx space equals space integral subscript straight a superscript 4 straight x to the power of 1 half end exponent dx
rightwards double arrow space space open square brackets fraction numerator straight x to the power of begin display style 3 over 2 end style end exponent over denominator begin display style 3 over 2 end style end fraction close square brackets subscript 0 superscript straight a space equals open square brackets fraction numerator straight x to the power of begin display style 3 over 2 end style end exponent over denominator begin display style 3 over 2 end style end fraction close square brackets subscript straight a superscript 4 space space space space space space space space space space space space space space space space space space space space space space space space rightwards double arrow space space space space space space open square brackets straight x to the power of 3 over 2 end exponent close square brackets subscript 0 superscript straight a space equals space open square brackets straight x to the power of 3 over 2 end exponent close square brackets subscript straight a superscript 4
rightwards double arrow space space space space straight a to the power of 3 over 2 end exponent minus 0 space equals space 4 to the power of 3 over 2 end exponent minus straight a to the power of 3 over 2 end exponent space space space space space space space space space space space space space space space space space space space space space space space rightwards double arrow space space 2 space straight a to the power of 3 over 2 end exponent space equals space 8 space space space rightwards double arrow space space straight a to the power of 3 over 2 end exponent space equals space 4 space space space space rightwards double arrow space space straight a space space equals 4 to the power of 4 over 3 end exponent

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