Inverse Trigonometric Functions

Find the value of the following : - Wired Faculty

Question

Find the value of the following :

$cos to the power of negative 1 end exponent open parentheses 1 half close parentheses plus 2 space sin to the power of negative 1 end exponent open parentheses 1 half close parentheses$

Solution

Let $straight y equals cos to the power of negative 1 end exponent open parentheses 1 half close parentheses space space space space space space space space space where space 0 less or equal than straight y less or equal than straight pi therefore space space space space space space cos space straight y equals 1 half space space space space space space where space 0 less or equal than straight y less or equal than straight pi therefore space space space space space space cos space space straight y space equals space cos space straight pi over 3 therefore space space space space space space straight y equals straight pi over 3 space space space space space space space rightwards double arrow space space space space cos to the power of negative 1 end exponent open parentheses 1 half close parentheses equals straight pi over 3 Again space let space straight z equals space sin to the power of negative 1 end exponent open parentheses 1 half close parentheses space space space space space space space where space minus straight pi over 2 less or equal than straight z less or equal than straight pi over 2 therefore space space space space space space sin space straight z equals 1 half space space space where space minus straight pi over 2 space less or equal than space straight z space less or equal than space straight pi over 2 therefore space space space space space space sin space straight z space equals space sin space straight pi over 6 therefore space space space space space straight z equals straight pi over 6 space space rightwards double arrow space space sin to the power of negative 1 end exponent open parentheses 1 half close parentheses equals straight pi over 6 Consider space cos to the power of negative 1 end exponent open parentheses 1 half close parentheses plus 2 space sin to the power of negative 1 end exponent open parentheses 1 half close parentheses equals straight pi over 3 plus 2 open parentheses straight pi over 6 close parentheses equals straight pi over 3 plus straight pi over 3 equals fraction numerator 2 straight pi over denominator 3 end fraction$

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Inverse Trigonometric Functions

Find the value of the following :

$cos to the power of negative 1 end exponent open parentheses 1 half close parentheses plus 2 space sin to the power of negative 1 end exponent open parentheses 1 half close parentheses$

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