-->

Integrals

Question
CBSEENMA12032402

Evaluate the following definite integral
integral subscript 0 superscript 1 fraction numerator 2 straight x over denominator 5 straight x squared plus 1 end fraction dx

Solution

Let I = integral subscript 0 superscript 1 fraction numerator 2 straight x over denominator 5 straight x squared plus 1 end fraction dx space equals space 1 fifth integral fraction numerator 10 straight x over denominator 5 straight x squared plus 1 end fraction dx
space space
       equals space 1 fifth left square bracket log left parenthesis 5 straight x squared plus 1 right parenthesis right square bracket subscript 0 superscript 1 space equals space 1 fifth left square bracket log space 6 space minus log space 1 right square bracket space equals space 1 fifth log 6

Some More Questions From Integrals Chapter