Explain the following integral:
$space integral subscript 0 superscript 1 fraction numerator 1 over denominator 1 plus straight x squared end fraction dx$

Solution

Let I = $integral subscript 0 superscript 1 fraction numerator dx over denominator 1 plus straight x squared end fraction space equals space left square bracket tan to the power of negative 1 end exponent straight x right square bracket subscript 0 superscript 1 space equals space tan to the power of negative 1 end exponent 1 minus tan to the power of negative 1 end exponent 0 space equals space straight pi over 4 minus 0 space equals space straight pi over 4$

For Daily Free Study Material Join wiredfaculty

Integrals

Explain the following integral:
$space integral subscript 0 superscript 1 fraction numerator 1 over denominator 1 plus straight x squared end fraction dx$

Some More Questions From Integrals Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Phone Number

Email Address

Loaction