-->

Integrals

Question
CBSEENMA12032382

Evaluate the following definite integral
integral subscript 0 superscript straight pi over 2 end superscript space cos space 2 straight x space dx








Solution

Let I = integral subscript 0 superscript straight pi over 2 end superscript space cos space 2 straight x space dx space equals space open square brackets fraction numerator sin space 2 straight x over denominator 2 end fraction close square brackets subscript 0 superscript straight pi over 2 end superscript space equals space 1 half left square bracket sin space 2 straight x right square bracket subscript 0 superscript straight pi over 2 end superscript space equals space 1 half left square bracket sin space space straight pi space minus space sin space 0 right square bracket space equals space 1 half left parenthesis 0 minus 0 right parenthesis space equals space 0

Some More Questions From Integrals Chapter