Evaluate the following definite integral
$integral subscript negative 1 end subscript superscript 1 left parenthesis straight x plus 1 right parenthesis space dx$

Solution

Let I = $integral subscript negative 1 end subscript superscript 1 left parenthesis straight x plus 1 right parenthesis space dx space equals space open square brackets fraction numerator left parenthesis straight x plus 1 right parenthesis squared over denominator 2 end fraction close square brackets subscript negative 1 end subscript superscript 1 space equals space 1 half space left square bracket left parenthesis straight x plus 1 right parenthesis squared right square bracket subscript negative 1 end subscript superscript 1$
$equals space 1 half open square brackets left parenthesis 1 plus 1 right parenthesis squared minus left parenthesis negative 1 plus 1 right parenthesis squared close square brackets space equals space 1 half left parenthesis 4 minus 0 right parenthesis space equals space 2$

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Integrals

Evaluate the following definite integral
$integral subscript negative 1 end subscript superscript 1 left parenthesis straight x plus 1 right parenthesis space dx$

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