+91-8076753736 support@wiredfaculty.com
logo
logo

Sponsor Area

Vector Algebra

Question
CBSEENMA12033987
Wired Faculty App

If PQ with rightwards arrow on top space equals space 3 straight i with hat on top space plus space 2 straight j with hat on top space minus space straight k with hat on top and the coordinates of P are (1, – 1, – 2), find the coordinates of Q.

Solution

Here P = (1, -1, -2)    rightwards double arrow   P.V. of P = straight i with hat on top space minus space straight j with hat on top space minus space 2 straight k with hat on top
Let Q be left parenthesis straight lambda subscript 1 comma space straight lambda subscript 2 comma space straight lambda subscript 3 right parenthesis
therefore space space space space straight P. straight V. space of space straight Q space equals space straight lambda subscript 1 straight i with hat on top space space plus space straight lambda subscript 2 straight j with hat on top space plus space straight lambda subscript 3 straight k with hat on top
Now,  PQ with rightwards arrow on top space equals space straight P. straight V. space of space straight Q space minus space straight P. straight V. space of space straight P
rightwards double arrow space space space space space 3 straight i with hat on top plus space 2 straight j with hat on top space minus space straight k with hat on top space equals space left parenthesis straight lambda subscript 1 straight i with hat on top space plus space straight lambda subscript 2 straight j with hat on top space plus space straight lambda subscript 3 straight k with hat on top right parenthesis space minus space left parenthesis straight i with hat on top space minus space straight j with hat on top space minus space 2 space straight k with hat on top right parenthesis rightwards double arrow space space space space 3 space straight i with hat on top space plus space 2 space straight j with hat on top space minus space straight k with hat on top space equals space left parenthesis straight lambda subscript 1 space minus space 1 right parenthesis straight i with hat on top space plus space left parenthesis straight lambda subscript 2 space plus space 1 right parenthesis space straight j with hat on top space plus space left parenthesis straight lambda subscript 3 space plus 2 right parenthesis space straight k with hat on top rightwards double arrow space space space 3 space equals space straight lambda subscript 1 space minus space 1 comma space space 2 space equals space straight lambda subscript 2 plus 1 comma space space minus 1 space equals space straight lambda subscript 3 plus 2 rightwards double arrow space space space straight lambda subscript 1 space equals space 4 comma space space space space space straight lambda subscript 2 space equals space 1 comma space space space straight lambda subscript 3 space equals space minus 3 comma therefore space space space space straight Q space is space left parenthesis 4 comma space 1 comma space minus 3 right parenthesis.

Some More Questions From Vector Algebra Chapter

Classify the following measures as scalars and vectors.
10–19 coulomb

Classify the following measures as scalars and vectors.
20 m/s2

Classify the following measures as scalars and vectors.
time period

Classify the following measures as scalars and vectors.
distance

Classify the following measures as scalars and vectors.
force

Classify the following measures as scalars and vectors.
velocity

Classify the following measures as scalars and vectors.
work done

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation