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Vector Algebra

Question
CBSEENMA12033976

Compute the magnitude of the following vectors:
straight a with rightwards arrow on top space equals space straight i with hat on top space plus space straight j with hat on top space plus space straight k with hat on top space space semicolon space space space straight b with rightwards arrow on top space equals space 2 straight i with hat on top space minus space 7 straight j with hat on top space minus space 3 straight k with hat on top semicolon space space straight c with rightwards arrow on top space equals space fraction numerator 1 over denominator square root of 3 end fraction straight i with hat on top space plus space fraction numerator 1 over denominator square root of 3 end fraction straight j with hat on top space minus space fraction numerator 1 over denominator square root of 3 end fraction straight k with hat on top

Solution

       straight a with rightwards arrow on top space equals space straight i with hat on top space plus space straight j with hat on top space plus space straight k with hat on top
therefore space space open vertical bar straight a with rightwards arrow on top close vertical bar space equals space square root of left parenthesis 1 right parenthesis squared plus left parenthesis 1 right parenthesis squared plus left parenthesis 1 right parenthesis squared end root space equals space square root of 1 plus 1 plus 1 end root space equals square root of 3
space space space space space space straight b with rightwards arrow on top space equals space 2 space straight i with hat on top space minus space 7 space straight j with hat on top space minus space 3 space straight k with hat on top
therefore space space open vertical bar straight b with rightwards arrow on top close vertical bar space equals space square root of left parenthesis 2 right parenthesis squared plus left parenthesis negative 7 right parenthesis squared plus left parenthesis negative 3 right parenthesis squared end root space equals space square root of 4 plus 49 plus 9 end root space equals space square root of 62
        straight c with rightwards arrow on top space equals space fraction numerator 1 over denominator square root of 3 end fraction straight i with hat on top space plus space fraction numerator 1 over denominator square root of 3 end fraction straight j with hat on top space minus space fraction numerator 1 over denominator square root of 3 end fraction straight k with hat on top
therefore space space space space space space open vertical bar straight c with rightwards arrow on top close vertical bar space equals space square root of open parentheses fraction numerator 1 over denominator square root of 3 end fraction close parentheses squared plus open parentheses fraction numerator 1 over denominator square root of 3 end fraction close parentheses squared plus open parentheses negative fraction numerator 1 over denominator square root of 3 end fraction close parentheses squared end root space equals space square root of 1 third plus 1 third plus 1 third end root equals space square root of 1 space equals 1