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Vector Algebra

Question
CBSEENMA12033965

ABCD is a quadrilateral and O is any point in its plane. Show that it OA with rightwards arrow on top space plus space OB with rightwards arrow on top space plus space OC with rightwards arrow on top space plus space OD with rightwards arrow on top space equals space 0 with rightwards arrow on top then O is the point of intersection of lines joining the middle points of the opposite sides of ABCD.

Solution

Let E. F, G, H be mid-points of the sides AB. BC. CD. DA respectively of quadrilateral ABCD.
∴    EFGH is a || gm    [From Co-ordinate Geometry]
∴  diagonals EG and FH bisect each other at P (say)
Now,    OA with rightwards arrow on top space plus space OB with rightwards arrow on top space plus space OC with rightwards arrow on top space plus space OD with rightwards arrow on top space equals space 0 with rightwards arrow on top
rightwards double arrow space space space open parentheses OA with rightwards arrow on top space plus space OB with rightwards arrow on top close parentheses space plus space open parentheses OC with rightwards arrow on top space plus space OD with rightwards arrow on top close parentheses space equals 0 with rightwards arrow on top
rightwards double arrow space space space space 2. space OE with rightwards arrow on top space plus space space 2 space OG with rightwards arrow on top space equals space 0 with rightwards arrow on top space space space space rightwards double arrow space space space space OE with rightwards arrow on top space plus space OG with rightwards arrow on top space equals space 0 with rightwards arrow on top
rightwards double arrow space space space space space 2 space OP with rightwards arrow on top space equals space 0 with rightwards arrow on top space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space open square brackets because space space straight P space is space the space mid minus point space of space EG close square brackets
rightwards double arrow space space space space space space space OP with rightwards arrow on top space equals space 0 with rightwards arrow on top

∴    O coincides with P which is the point of intersection of lines joining the middle points of the opposite sides of ABCD.