Suppose that 90% of people are right-handed. What is the probability that at most 6 of a random sample of 10 people are right-handed?

Solution

Here n = 10
$straight p space equals 90 over 100 space equals 9 over 10 comma space space space straight q space equals space 1 space minus space straight p space equals space 1 minus space 9 over 10 space equals space 1 over 10$
Required probability $equals space space straight P left parenthesis straight X space less or equal than space 6 right parenthesis$
$equals space 1 minus straight P left parenthesis 7 space less or equal than straight X less or equal than 10 right parenthesis space equals space 1 minus space sum from straight r space equals space 7 to 10 of space space straight C presuperscript 10 subscript straight r space open parentheses 1 over 10 close parentheses to the power of 10 minus straight r end exponent space open parentheses 9 over 10 close parentheses to the power of straight r$

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Probability

Suppose that 90% of people are right-handed. What is the probability that at most 6 of a random sample of 10 people are right-handed?

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