Question
If a fair coin is tossed 10 times, find the probability of
(i) exactly six heads
(ii) at least six heads
(iii) at most six heads
Solution
Here n = 10
P = Probability of head =
(i) P(exactly six heads) = P(6)
(ii) P(at least six heads) = P(6) + P(7) + P(8) + P(9) + P(10)
(iii) P(at most sixes) = P(0) + P(1) + P(2) + P(3) + P(4) + P(5) + P(6)