An unbiased coin is tossed six times. Find the probability of obtaining at most 4 heads.

Solution

Here n = 6
p = Probability of head = $1 half comma space space straight q space equals space 1 space minus space straight p space equals space 1 minus 1 half space equals 1 half$
P (at most 4 heads) = 1 - [P (5) + P (6)]
$equals space 1 minus space open square brackets straight C presuperscript 6 subscript 5 space open parentheses 1 half close parentheses space open parentheses 1 half close parentheses to the power of 5 space plus space straight C presuperscript 6 subscript 6 space open parentheses 1 half close parentheses to the power of 6 close square brackets space equals space 1 minus 1 over 64 space open square brackets 6 over 1 plus 1 over 1 close square brackets space equals space 1 minus 7 over 64 space equals 57 over 64$

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Probability

An unbiased coin is tossed six times. Find the probability of obtaining at most 4 heads.

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